(4x+5)^2-80x=(4x-5)

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Solution for (4x+5)^2-80x=(4x-5) equation: 



(4x+5)^2-80x=(4x-5)

We move all terms to the left:

(4x+5)^2-80x-((4x-5))=0

We add all the numbers together, and all the variables

-80x+(4x+5)^2-((4x-5))=0



We calculate terms in parentheses: -((4x-5)), so:

(4x-5)

We get rid of parentheses

4x-5

Back to the equation:

-(4x-5)



We get rid of parentheses

-80x+(4x+5)^2-4x+5=0

We add all the numbers together, and all the variables

-84x+(4x+5)^2+5=0

We move all terms containing x to the left, all other terms to the right

-84x+(4x+5)^2=-5

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